Rotation
Kinetic equation of rotating rigid body
= 0 + t
= 0t + f
2 = 02 + 2 
- Moment of inertia
I = 
- Radius of Gyration
I = Mk2
That is, k is the distance of the point mass M from the axis of rotation such that this point mass has the same moment of inertia about that axis as the given body.
- Theorem of parallel Axes
I = ICM + Md2
- Theorem of perpendicular Axes
Iz = Ix + Iy
- Rotational kinetic energy
Consider a rigid body rotating about a fixed axis with angular velocity w. The body can be supposed to be made up of a large number of particles m1, m2 . . . , mn at distances r1, r2, . . . , rn respectively, from the axis of rotation. Each particle has a kinetic energy. The kinetic energy of the body will be sum of the kinetic energies of all the particles. IF 1, 2, . . . , n be the linear speeds of the particles, respectively, then the kinetic energy of the body can be written as
Ek = 
- Torque
= F × d = Fr sin 
In vector notation

- Angular momentum

- Relation between t & L

- Work done by a torque
dW = d
W = 
- Relation between Torque and Angular acceleration
= I
- Work-Energy Theorem
W = 
- Relation between Angular momentum and Angular velocity
L = I
- For slipping body
ET = 
- For spinning body
ER = 
- For rolling body
EN = 
- Rolling without slipping
En = 
Rolling on an inclined plane
- Velocity at lower point v =

- Acceleration in motion a =

- Time of descent t =

Motion of connected mass
- Downward acceleration of point mass
a = 
- Tension in string
T = mg 
- Velocity of point mass
v = 
- Angular velocity of rigid body
= 
Moment of inertia of different bodies
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