One dimensional Motion


One dimensional Motion (xi)
  • Speed


  • Average speed


  • Instantaneous speed


  • Acceleration


  • Average acceleration


  • Instantaneous acceleration


  • Equations of Kinematics

    a) V = u + at b) S = ut + 1/2 at2

    c) V2 - u2 = 2as d) 
  • Displacement of the particle in the nth second is


  • For a particle projected up; g is conventionaly taken negative and positive if it is falling, u = 0

    a) Velocity attained after falling for a time 't' is V = gt

    b) Distance fallen in a time t is h = gt2

    c) Time taken to fall a distance h is 

    d) Velocity attained after falling a distance h is 

    e) Distance travelled in the nth sec, is Sn(2n-1)
  • If a body is thrown downward with a velocity u. Equations of motion are :

    a) V = u + gt b) v2- u2 = 2gh

    c) h = ut + gt2 d) Sn = u + (2n-1)
  • If a particle is projected vertically up with a velocity U, acceleration is a = - g,

    Equation of motion are



    a) h = ut - gt2 b) v = u - gt

    c) v2 - u2 = -2gh d) Sn = u - (2n-1)
  • for maximum height v = 0,

    (a) Hmax =  (b) t = 

    I u = 
  • If an object is dropped from a ballon rising up with a velocity u at a height h.

    (i) Equation of motion relative to earth is h = - ut + gt2

    ii) Equation of motion relative to ballon is h = gt2
  • If a body is projected vertically up with a velocity u from a tower and it reaches the ground with a relative nu., the height of the tower is .
  • A elevator is accelerating upwards with an acceleration a. If a person inside the elevator throws a particle vertically up with a velocity u relative to the elevator, time of flight is 
  • In the above case if elevator accelerates down, time of flight is  
  • If a body is projected with a velocity u at an angle q to the horizontal.



    Projectile (XI)
  • Vertical displacement at any time t.

    y = (u sin ) t - 1/2 gt2
  • Vertical component of velocity

    Vy = u sin  - gt.
  • Equation of trajectory

    y = x tan  - 
  • Time taken to reach the maximum height

    t = 
  • Maximum height attained

    Hmax = 
  • Time of flight

    T = 
  • Range

    R = 

    Rmax = 

    tan  = 

    R = 1/2 g L1 L2
  • If R is maximum, Hmax = R/4.
  • If R = Hmax = tan -1 (4)  760.
  • (P.E.) = 1/2 mu2 sin .
  • (K.E.) = 1/2 mu2 cos2.

    Horizontal projectile 
  • Position after time t: 


  • Horizontal displacement after time t. x = ut
  • Distance fallen in time "t" y = gt2
  • Equation of path .
  • Time of flight

    T = 
  • Horizontal Range

    R = 

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